Sentences with phrase «co2 absorbing another photon»

Not exact matches

I would like to get an idea of how much of the energy a CO2 molecule acquires when absorbing a 15um photon ends up re-emitted as an infra - red photon.

It can be reasonably calculated from available extinction coefficients and CO2 concentration that > 99 % of the IR photons emitted by the earth's surface that can be absorbed by CO2 will be absorbed in the first 100m.

Vibrational modes in molecules with three or more atoms (H2O, CO2, O3, N2O, CH4, CFCs, HFCs...) include bending motions that are easier to excite and so will absorb and emit lower energy photons which co-incide with the infrared radiation that the Earth emits.

Briefly put, the process can be defined as a CO2 molecule absorbing a ~ 650 cm - 1 photon (equivalent to a thermal energy of about 900 K), and losing that energy to the surrounding bath of atmospheric gases.

If there is a greater density of CO2 molecules, then the probability of a particular photon, at one of these wavelengths that CO2 absorbs, coming across a CO2 molecule, is clearly increased.

What is relevant is the probability that such a photon will be absorbed by (or more generally interact with) a susceptible molecule (CO2) within the given length.

What I'm saying is that TOA, as far as radiative energy is concerned, for CO2 or other IR absorbing gas, is effectively the altitude where the chance that a photon will be absorbed, and emitted back in a direction that will lead it to being absorbed again by a molecule in the atmosphere, becomes negligible.

Do photons from the surface of the earth heat up the CO2 molecules that absorb them (where heating up would mean making them move faster), and transmit this heat to other air molecules by collision.

Ray: «The IR flux from the warmer surface excites much of the CO2 — much more than would be excited at thermal equilibrium at the temperature of the atmospheric layer where the photon is absorbed.»

How long does a CO2 molecule at 5.5 kms height hold on to that absorbed IR photon before it is released (emitted or transferred though collision to another atmospheric molecule)?

under intense IR radiation CO2 will effective «fill up» and become saturated, unable to absorb any more until it has emitted some IR photons?

A poor strawman argument rebutal from David Wojick: «CO2 does not re-emit the photons that it absorbs.»

So the surface of the Earth absorbs two identical 15 micron photons which carry the same energy, one originates from a colder CO2 molecule and the other from the surface of the Sun.

So, it seems to me that the amount of energy absorbed by CO2 in the bands that can be absorbed by CO2 (ie, some fraction of the total outgoing energy) is proportional to the fraction of CO2 in the atmosphere, unless you can somehow magically push all that CO2 into a thin shell that no photon of the required frequency can avoid.

By the way, CO2 does not re-emit the photons that it absorbs.

If the CO2 simply re-emits the LW photons it absorbs, then how does it heat the air, that is the N and O2, which is what the greenhouse effect does?

Your exact words were: «CO2 does not re-emit the photons that it absorbs.

The GHGs like CO2 do emit photons, which go up and down, but they are not the photons that they absorb.

All of the IR photons in CO2's absorption bands are absorbed quickly — within less than a meter, I think.

You do know that plant life absorbs photons and CO2, which is buffered by inorganic carbonate, and convert it to organic carbon.

Let's say a CO2 molecule in the atmosphere absorbs an IR photon.

Radon is radioactive, and if it were present at 400 ppm, collisions of neutrons with neighboring air molecules would cause more warming than an equivalent concentration of CO2 by absorbing relatively weak infrared waves / photons.

Hit that lone CO2 with a 15 micro-meter photon of infrared light and let it absorb the photon.

What CO2 does do is it absorbs and then 100 attoseconds later, emits Infrared photons, or radiant heat.

Therefore in order to maintain the number of vibrationally excited molecules constant, every time a CO2 molecule absorbs an infrared photon and excites vibrationally, it is necessary that another CO2 molecule relaxes by going to a lower energy state.

Help me here... A system in equilibrium quickly returns to equilibrium at a higher level when it absorbs an IR photon: CO2 + N2CO2 + N2 becomes CO2 * + N2CO2 + N2 + (pardon the limited special character skills).

My understanding is that approximately 85 % of all photons in the Earth's blackbody spectrum that are also in the absorbtion spectrum of CO2 are already presently being absorbed at the present concentration of atmospheric CO2.

How does a CO2 molecule, somewhere up in the middle troposphere, KNOW that it is only allowed to absorb upwelling radiation photons from the surface and must ignore all the other photons coming at it from all around in the atmosphere?

It also appears that CO2 is emitting as a result of collision and not absorbing photons and passing the energy to O2 / N2

To have any effect, you need enough CO2 that the average distance an IR photon travels before being absorbed would have to be a very small fraction of the distance between the walls.

The standard tables for absorption of photons by CO2 show that at STP, 50 % of photons are absorbed within 25m and 50m for wavenumbers 650, and 700 respectively.

Radiation at these wavelengths can not be radiated directly into space from the surface because these photons are easily absorbed by water and CO2 molecules.

To explain these differences in models you need to look inside the CO2 molecule and understand what happens to excess neutrons, because it is these heavy particles that vibrate and absorb excess IR photons and are the probable reason for the 1910 to 1940 temperature rise.

Plants absorbs high energy photons, which results in the combining of CO2 and H20 into CH2O and O2.

4) The second - generation photons going upwards will be absorbed by CO2 (and H2O) molecules that are in the layer of air above the 120 meter line and they will be absorbed to extinction in about another 120 meters or so.

Wayne, Robert Stevenson and others have made the point that, given current concentrations of CO2 and H2O and other so - called «greenhouse gases», the first - generation photons from the Surface up into the Atmosphere are absorbed to extinction in 120 meters or some other relatively small distance compared to the total height of the Atmosphere.

1) ~ 15μm LWIR photons emtted by the Earth pass into the lower 120 meters of Atmosphere and all are absorbed by CO2 (and H2O) molecules.

2) The CO2 (and H2O) molecules that absorbed those first - generation photons are energized.

Because of its high concentration, water vapour absorbs to extinction first generation photons (hv) in the main waveband in 120m of traverse (as many contributors have pointed out) and CO2 absorbs very little, due to its small concentration.

I would not be surprised if my numbers are off by 10x or possibly even 100x, but that still doesn't cahnge the fact that there are plenty of CO2 molecules around to absorb photons even at an «insignificant 0.04 %» concentration.)

Whether there is 0.03 % or 0.04 % of CO2 in the atmosphere only influences how often the photons get absorbed and re-radiated on their way to space — an increase in CO2 delays the process a little but does not change it fundamentally and * Does * * Not * * Trap * * Heat * any more than a sieve traps water.

The same argument applies to water vapour but with a larger absorption number for first generation photons (say about 200W / m ^ 2 absorbed in a shorter extinction distance and about the same in the remainder shooting off to space; compared with about 80W / m ^ 2 absorbed for CO2 etc).

A common fallacy is that CO2 molecules emit a photon of the same frequency as that absorbed.

And the CO2 molecule only «holds» that energy for a faction of a second, so a given molecule could in principle absorb many photons every second.

A doubling of CO2 would not absorb any more (extra) first generation photons but the distance to the extinction point would reduce to Lm / 2.

Phil, what do your calculations give for the distance in which the first - generation photons from the Surface up into the atmosphere are absorbed to extinction in CO2's case?

A radiated IR photon is going to be absorbed directly, and not wait around for man to release CO2 to cause warming to cause more water vapor molecules!

So Gavin, you are claiming that in the GHE when a photon comes in it sits around in the air until man releases CO2 which results in warming which results in more water vapor which THEN absorbs the energy photon to create feedback?

(eg water in the ocean) Specifically I contend that there is not enough photon energy available so that ALL added CO2 or water vapor (in the case of feedback) WILL absorb a photon to contribute to the GHE.

As I understand AGW, the theory goes that added CO2 combines with an energy photon (ie the greenhouse effect) to warm the world, & heat the air which results in more water vapor which absorbs more photons which results in Man caused warming feedback.