Now surround body «B» with body «A», which is also a thin spherical shell (external radius RE) with internal and external black
body radiating surfaces, but contains no internal radioactive energy source.
Not exact matches
The Stefan — Boltzmann law states that the total energy
radiated per unit
surface area of a black
body across all wavelengths per unit time (also known as the black -
body emissive power) is directly proportional to the fourth power of the black
body's absolute temperature.
How can the earth be
radiating a crude BB type spectrum corresponding to the
surface Temperature when Trenberth claims that only 40 W / m ^ 2 escapes to space in the atmospheric window, and folks insist that the main
body of the atmosphere (gases) does not emit thermal radiation.
The sea
surface radiates IR like any other black
body.
For the up / down /» back» radiation of greenhouse theory's GHG energy loop to function as advertised earth's «
surface» must
radiate as an ideal black
body, i.e. 16 C / 289 K, 1.0 emissivity = 396 W / m ^ 2.
Further assume that the shell's internal and external
surfaces radiate as a black
body.
As I recall, this is based on the theory that the structure of the black
body surface is so complex that it has a continuous spectrum of oscillatory mechanisms and can thus
radiate or absorb at any frequency with equal probability.
For these conditions, when radiation - rate - equilibrium is reached for the «two - shell system» (i.e., when the rate of energy being
radiated outward by the outer shell equals the rate of energy being generated in the wall of the inner shell, I believe the presence of
body «A» will affect the temperature of the external
surface of the inner shell.
The rate of energy
radiated by a block
body at temperature T Kelvins is proportional to the fourth power of T and the
surface area A of the black
body.
When you have two
radiating bodies, in this case the Earth's
surface and the adjacent atmosphere at nearly the same temperature, the two radiation fields interact such that the net energy transfer is the vector sum of the Poynting Vectors over all the wavelengths.
These stem from a diversity of site - specific conditions, including, but not limited to: local vegetation; presence of building structures and contributions made by such structures involving energy use, heating and air conditioning, etc; exposure to winds, the wind velocities determined by climatic factors and also whether certain wind directions are more favored than others by terrain or the presence or absence thereof to
bodies of water; proximity to grass, asphalt, concrete or other material
surfaces; the physical conditions of the CRS itself which include: the exact location of the temperature sensors within it, the degree of unimpeded flow of external air through the CRS, the character of the paint used; the exact height of the instrument above the external
surface (noting that when the ground is covered by 3 feet of snow, the temperature instrument is about 60 % closer to, or less than 2 feet, above an excellent
radiating surface, much closer than it would be under snow - free conditions).
One who at rest produces 100 W through his metabolism, but
radiates over 500 W from his
body surface?
This 3.7 W / m ^ 2 is captured by the atmosphere, which
radiates it, as a grey
body,
radiates it in all directions so that half is
radiated to the
surface and half into space.
Excluding the absorbed part from the sky, which maybe you dispute anyway, the emission is hundreds of W / m2, as would be expected for a water
surface radiating almost like a black
body.
Radiation comes in from the sun (solar radiation at short wavelengths), and every
body radiates according to its temperature (proportional to the fourth power of absolute temperature), so that on Earth we, and the
surface and atmosphere
radiate at infrared wavelengths.
The point is not about comparing (1) the heat conserving power of CO2 as a «
radiating body» (the main beef of the «greenhouse theory») to the insulating power of a metal coated
surface but to (2) the heat losing power of CO2 by conduction.
Thus, if the base black
body radiates 235 watts per square meter and sized to be 1 square meter and the shell is sized to be 2 square meters on the interior
surface, then the shell would be
radiating 117.5 watts per meter squared from it's
surface, but that gets concentrated to 235 watts when it finally reaches the
surface of the base black
body sphere.
As a result of (2) and at equilibrium all of the thermal energy of the Earth's
surface would have to be
radiated directly into space by the black
body Earth itself.
«The Stefan — Boltzmann law states that the total energy
radiated per unit
surface area of a black
body across all wavelengths per unit time (also known as the black -
body radiant emittance or radiant exitance) is directly proportional to the fourth power of the black
body's thermodynamic temperature».
I'd say that it is also possible to arrive at the temperature difference between the black
body radiating temperature and the average
surface temperature without any recourse to radiant heating (adiabatic compression by gravity) and same for the
surface temperature on the
surface of venus.
...
bodies situated on or near to the
surface of the earth become, under certain circumstances, colder than the neighbouring air, by
radiating more heat to the heavens than they receive in every way...
The measured radiative spetrum of the Earth's thermal radiation demonstratesm that the spectrum closely approximates that of a black
body with an absolute temperature of the
radiating part of the Earth's
surface being measured.
The Planck response applies to a
radiating body with a single distinct
surface.
... similarly dense clouds, if very high, though they equally intercept the communication of the earth with the sky, yet being, from their elevated situation, colder than the earth, will
radiate to it less heat than they receive from it, and may, consequently, admit of
bodies on its
surface becoming several degrees colder than the air.
So the atmosphere does
radiate a black
body like thermal spectrum, and the presence of the gHG molecules simply means that there will be bands of that continuum emission, that are also captured by the GHG molecules, as well as the emissions from the
surface.
And restricting the
surface from
radiating, or returning a portion of that emission back to it, causes the
body to cool slower.