Sentences with phrase «energy ke»

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Not exact matches

It's light on plot and high on energy and life — a movie worthy of mention in the same hot breath as Truffaut's The 400 Blows and Loach's Kes.

Poster display showing symbolic representation and simple definitions of light energy, kinetic energy (KE), heat energy, sound energy, electrical energy and potential energy (PE).

Snatch towing or more properly kinetic energy recovery is something that a stretchy rope is good for - can't do that with a solid bar - the likelihood of something breaking is very high, but KE recovery needs the mounting points to be perfect: have seen a chassis member come off before...

Maximum incoming solar heating occurs there but the greatest temperatures are near 50 km where the low density air requires very little energy to raise its temperature (think KE = 1/2 mv ^ 2 and fewer collisions with fewer air molecules yield greater v).

I also explained why the extra warmth at the surface is provided by compression of descending air converting potential energy (PE) to kinetic energy (KE) and not from downward radiation from GHGs in the air warming the ground beneath.

12) The answer is that due to any such imbalance the normal equilibrium distribution of Kinetic Energy (KE) and Potential Energy (PE) is upset and parcels of air start to move around differently relative to each other due to the changes in their respective KE and PE contents.

Heat (not latent heat) is removed prior to condensation by conversion of kinetic energy to potential energy which then provokes condensation and when the phase change occurs the release of latent heat causes the air parcel to rise a little further with additional conversion of KE to PE until it reaches the correct lapse rate temperature for its height and then it stops rising and begins to descend.

Since angular momentum is linear in angular velocity while rotational energy is quadratic, such an exchange will indeed involve converting an excess of KE to some other form, though considerably less than 2e22 J. Redo your math and you'll see just how much less.

In order to unbalance KE and PE through the entire vertical column of the AAL requires that there be more total energy available to the system but established science says that can only occur from more mass, gravity or insolation.

(i) If one increases GHGs to slow down energy flow through the diabatic loop thereby warming that loop there will be an increase in PE relative to KE within the adiabatic loop instead of a change in the constant.

Instead of transferring more energy from SDL to AAL the effect of changes in the proportion of radiatively active gases would simply be to adjust the speed of the AAL by changing the height within the vertical column at which KE = PE.

There is, therefore, considerable flexibility in the speed at which it can operate and unless KE and PE become unbalanced throughout the entire vertical column then no energy can be transferred between the AAL and the SDL.

(ii) If one decreases GHGs to speed up the energy flow through the diabatic loop thereby cooling that loop there will be a reduction in PE relative to KE within the adiabatic loop instead of a change in the constant.

If there were to be a sealed cylinder of air which was isothermal, then there would be an «ordered» state with more total energy (PE + KE) at the top.

Doug, You write «If there were to be a sealed cylinder of air which was isothermal, then there would be an «ordered» state with more total energy (PE + KE) at the top.

The poles can only be that hot if diffusion of KE can cause absorbed thermal energy from the Sun (KE) to appear to pass up the temperature gradient.

Your bold: No, the Equipartition Theorem says the temperature (not «heat») of a gas is due to translational, vibrational and rotational kinetic energy (KE.)

Solar energy can push a solar sail [but a solar sail is in fixed location unlike gas molecules - but I would not throw out idea that sunlight can increase the KE of gas molecules in some manner - but would seem in most cases to be rather insignificant].

These Photons have a separate existence to the molecules about them & don't present any indication of the Kinetic Energy (KE) of those surrounding molecules, whose KE is presented as the VELOCITY of the molecular unit and is measured in style as «Temperature» (or as Pressure also).

Infact the Energy of the Photons within the Cascade is that Energy NOT involved in any induction of KE, yet it is THIS energy that «greenhouse science» attempts to cite as «temperature» when using CO2 as a temperature proxy, and this methodology invalidates ALL other supposed «greenhouse proxies»Energy of the Photons within the Cascade is that Energy NOT involved in any induction of KE, yet it is THIS energy that «greenhouse science» attempts to cite as «temperature» when using CO2 as a temperature proxy, and this methodology invalidates ALL other supposed «greenhouse proxies»Energy NOT involved in any induction of KE, yet it is THIS energy that «greenhouse science» attempts to cite as «temperature» when using CO2 as a temperature proxy, and this methodology invalidates ALL other supposed «greenhouse proxies»energy that «greenhouse science» attempts to cite as «temperature» when using CO2 as a temperature proxy, and this methodology invalidates ALL other supposed «greenhouse proxies» also.

Realise that H2O has a very low remittance behavior, retaining absorbed energy as a gain in intrinsic KE manifested as increase in kinetic velocity of the molecular unit.

By your hypothesis, since the Kr has gained more PE, the Kr must have less KE to have the same total energy.

For starters, we'd expect that if the average energy of the entire system increased, so there was more kinetic energy at the surface, that the atmosphere would «puff up» from the Earth and it's edge would get higher due to more KE being available for transforming into PE.

Notice that every time you see total energy equation written in thermo theory — it looks something like this: total energy = TE = PE + KE = constant.

As implausible as it might seem at first, the average kinetic energy of the molecules that make it 17 km will be the same as the average KE of the molecules at the bottom.

For two particles, KE does not need to drop to zero when mgh = e, because it would be possible for one particle to have 2e of total energy, and have KE = PE = e at that altitude.

For example, in a solid there are only three axes, but there is KE and PE associated with each axis, so there are SIX degrees of freedom and each will have an average energy 1/2 kT when averaged over sufficiently long periods of time.

This SCIENCE begins with noticing that it is kinetic energy (KE) that is not involved directly within the processes of Turbulence that can be measured as a Temperature of the mass being affected by turbulence, be it within the Ocean and / or the Atmosphere.

No, PE is not part of the thermal energy; PE is a component of the molecule's total energy constant TE = 1 / 2mv ^ 2 + mgh = KE + PE.

The (microwave) energy within the Infrared Region (IrR) will not produce «sun burn» (a mild radiation burn from UV - A and UV - B) but would induct too much intrinsic KE (measured as temperature) in outer cellular structures, stopping internal cellular processes, killing those cells, and preventing even the formation of «life» not only «as we know it», but as «we are».

And likewise the KE (thermal energy) of the molecules must increase as they move downhill with gravity.

Certainly neither bulk KE nor bulk PE nor bulk RE (rotational energy) nor bulk VE (vibrational energy) is part of thermal energy.

The temperature or mean kinetic energy of the molecules it will measure will be different: KE (h) = C — mgh.

The system is already at maximum entropy with the thermal gradient maintained by gravity due to the fact the KE (thermal energy) of the molecules must decrease with height as they move uphill against gravity.

Constant 1 molecule total energy = KE + PE.

If the particles do not obey MB statistics, and they probably won't for small numbers, the justification for converting average kinetic energy to temperature using MB statistics (2/3 KE / k) no longer exists.

(Say it again: Deduce from 1st Law: molecule (s) KE or temperature must vary in a gravity field with PE, for total energy to be constant, OMG!)

The microscopic argument has already been made (that only self - selected high - energy molecules make it that high, and even after losing some PE, they STILL have the same averge KE left).

DeWitt Payne: «If the particles do not obey MB statistics, and they probably won't for small numbers, the justification for converting average kinetic energy to temperature using MB statistics (2/3 KE / k) no longer exists.»

Maximum entropy is all molecules (on average, not at the microscopic level) have equal total energy TE = PE + KE.

My point is that the gas is doing work on itself (and in that sense the expansion isn't «free»), and that the directed radial motion that results is not thermal energy; this KE would contribute to the gas's temperature again if the expansion were reversed isentropically, or the gas hit a wall and randomised it irreversibly, but not if it were instead extracted from the bulk flow by eg turbines or pistons.

The molecule's thermal energy is KE i.e. temperature which is ~ speed of the molecule, this speed decreases as the molecule climbs against the gravity field, hence T decreases, even in equilibrium.

KE energy of a particle is indeed constant — > when averaged over long periods of time.

All the while keeping their total energy (KE + PE) constant.

Since when the molecule comes back at any level L with the very same potential energy that it had on the way up at that level, and since TE is conserved, KE, (and hence also scalar velocity,) must * also * be the same.

Kelleher Environmental (KE) is an environmental consulting company based in Toronto, Ontario, Canada which specializes in environmental research and policy development; energy conservation, climate change and green energy; waste diversion policy development, planning, implementation and evaluation; and facilitation, adult education and environmental training.

You repeat for the 20th time is it that the average KE of the molecules in equal at every level Z because some don't have the energy to travel further.

By your own acknowledgement, for any given molecule, total energy TE = KE + PE, where «TE» is conserved throughout the free fall trajectory.