Sentences with phrase «gas absorbs a photon»

If a cold greenhouse gas absorbs a photon emitted from the ground, and emits at a lower intensity, where does the rest of the energy go?

Not exact matches

If an atom absorbs a single photon, its change in velocity is tiny compared with the average velocity of atoms in a gas at room temperature.

That's because the gas can be used to make several of the layers in a silicon photovoltaic — from the top of the cell where it is used to deposit a layer of silicon nitride that ensures that all sunlight is absorbed, to the bottom where it can be used to deposit another layer that helps reflect back any missed photons of sunlight, boosting the efficiency of the cell at converting light into electricity.

In doing so, as the CMB photons traveled through this hydrogen gas, it absorbed a particular frequency — so rather than look for a specific emission, astronomers have been looking for a specific type of absorption, or a certain frequency of CMB radiation that was missing.

If EM is passing through the gas molecules, they may absorb photons.

Briefly put, the process can be defined as a CO2 molecule absorbing a ~ 650 cm - 1 photon (equivalent to a thermal energy of about 900 K), and losing that energy to the surrounding bath of atmospheric gases.

I don't have a mathematical argument for my claim, just a physical one, which is that as photons pass through a gas they're either absorbed or not.

What I'm saying is that TOA, as far as radiative energy is concerned, for CO2 or other IR absorbing gas, is effectively the altitude where the chance that a photon will be absorbed, and emitted back in a direction that will lead it to being absorbed again by a molecule in the atmosphere, becomes negligible.

Re 392 Chris Dudley — while it makes intuitive sense that a spatially - invariant net photon flux could be sustained by a constant gradient in local equilibrium photon concentration (proportional to T ^ 4 for a grey gas, assuming constant real component of index of refraction), the calculation of what that gradient should actually be is made a bit more complicated by the fact that photons travelling in different directions will on average be absorbed over longer or shorter vertical distances.

The other part is an extension of that that describes how photons are absorbed and emitted in a large space filled by gas, the atmosphere (also clouds must be taken into account).

Thus, the phase change of water from liquid to gas, after absorbing photons, is a feedback, the absorption of photons and the emission of photons atmospheric water vapor is a forcing, but the photons released when gaseous water become liquid water is a feedback.

It would still pick up heat from direct conduction, as Gary Moran has insisted; and it would not be correct to say that there would be NO interaction with radiation (another point by Tom Vonk): if there are lower - energy bands, they will be used by the gas to absorb photons.

-- For the photons of interest, it is only the GHGs that are absorbing / emitting: if gas molecules don't have quantum transitions with the right energy differences, they can't interact with the photons.

At certain wavelengths a radiatively active gas will absorb photons and then reemit them in a random directions.

I agree that the 2nd Law has been misapplied, all you've got is gas molecules and photons milling about randomly, they don't stop and think what «The 2nd Law» expects them to do, some photons from the atmosphere DO get absorbed by the surface, making it warmer than it would otherwise be.

That implies that an excited electron in a greenhouse gas molecule in the atmosphere can not radiate toward the ground unless it can «find» another electron on the surface in a ground state which is capable of absorbing the photon which is to be radiated.

Wayne, Robert Stevenson and others have made the point that, given current concentrations of CO2 and H2O and other so - called «greenhouse gases», the first - generation photons from the Surface up into the Atmosphere are absorbed to extinction in 120 meters or some other relatively small distance compared to the total height of the Atmosphere.

Given that there are «greenhouse gases» above Wayne's line, most of the upward - going photons from below Wayne's line will be absorbed in «just 10's of meters».

If you know the energies of the allowed orbits, you can find the energies of photons that can be absorbed or emitted by other gases.

However, it is an observed fact (supported by theory) that monatomic gases (like argon) or symmetric diatomic gases (like N2 and O2) do not have vibration modes or rotation modes that would allow them to absorb (or emit) IR photons.

The atmosphere DOES go deep enough to eventually absorb all the photons — and it is a plasma not a gas.)

The main thing to correct in this explanation is that the CO2 and H2O will not emit in wavelengths that they don't absorb, so none of the 10 micron photons reaching space will have been emitted by the CO2 or H2O gas.