Sentences with phrase «works at a constant temperature»

Not exact matches

This time, because I was working with a larger batch of chocolates, I failed at trying to keep the melted chocolate at a constant temperature.

Warm mist humidifiers work by heating water and cooling it down to a preset temperature, and they help asthmatics by increasing the humidity at a constant temperature.

I'd like something I can travel with, not just something that works well sitting on my counter at constant room temperature.

The works on display are: 432Hz (2009 - 2014), a wooden shell that contains honeycombs; Vorkuta (2003), a refrigeration chamber where the temperature of -30 °C contrasts with a chair maintained at a constant +37 °C by an internal thermostat; Mindfall (2004 - 2007), a container which contains a chair and tables, on which 21 electric motors turn on intermittently, one after the other, creating a sort of musical composition; Untitled (2003), a small iron room crossed by blasts of hot and cold air channelled into the space by powerful fans; and Sub (2014), a new work specially created for the exhibition at HangarBicocca, an assembly of aluminium and glass display units which the artist originally designed to exhibit her Inner Disorder (1999 - 2001) series of drawings.

However they failed to realise that Global warming is an on / off phenomena and sp had no answer to the current constant average temperature, They failed to understand the 1940 singularity, so they did not have a clear view of the processes at work.

Here how it works: Think of the ocean as an open pot of warm water with constant heat input (TSI) at a level where water is held at constant temperature by evaporation and internal convection.

The corresponding working quasilinear wave equation for the barotropic azonal stream function Ψm ′ of the forced waves with m = 6, 7, and 8 (m waves) with nonzero right - hand side (forcing + eddy friction) yields (34) u˜ ∂ ∂ x (∂ 2Ψm ′ ∂ x2 + ∂ 2Ψm ′ ∂ y2) + β˜ ∂ Ψm ′ ∂ x = 2Ω sin ϕ cos2 ϕT˜u˜ ∂ Tm ′ ∂ x − 2Ω sin ϕcos2 ϕHκu˜ ∂ hor, m ∂ x − (kha2 + kzH2)(∂ 2Ψm ′ ∂ x2 + ∂ 2Ψm ′ ∂ y2), [S3] where x = aλ and y = a ln -LSB-(1 + sin ϕ) / cos ϕ] are the coordinates of the Mercator projection of Earth's sphere, with λ as the longitude, H is the characteristic value of the atmospheric density vertical scale, T˜ is a constant reference temperature at the EBL, Tm ′ is the m component of azonal temperature at this level, u˜ = u ¯ / cos ϕ, κ is the ratio of the zonally averaged module of the geostrophic wind at the top of the PBL to that at the EBL (53), hor, m is the m component of the large - scale orography height, and kh and kz are the horizontal and vertical eddy diffusion coefficients.

You have presented in top post a manifestly incorrect constant temperature gradient solution to your stated Fig. 1 conditions, i.e. incorrectly isothermal & can be manifestly shown to NOT be at maximum entropy isothermally therefore not at equilibrium thru some hard work.

So if one uses the heat engine to do external work, the gas in the cylinder will indeed drop to zero in temperature as all of its internal energy drops to the bottom to maintain a constant temperature difference right up to where the temperature of the ideal gas at the top reaches zero.

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