Sentences with phrase «years time period =»

For my daugthers education - 13 years time period = ICICI Prudential focused Bluechip eq fund - Growth - 10K 2.

Not exact matches

While floaters may be linked to almost any benchmark and pay interest based on a variety of formulas, the most basic type pays a coupon equal to some widely followed interest rate or a change in a given index over a defined time period, such as the year - over-year change in the Consumer Price Index (CPI), plus a fixed spread in basis points (1bp = 1/100 of 1 % or.01 %).

= > boy, good luck reconciling that with the fossil record which shows punctuated equilibrium: stasis for millions of years followed by a grand paroxysm of neccessarily interdependant mutations in a short period of time.

Based on photographs taken between 1937 and 1970, Sarah Lee Lippincott reported in 1971 that star A and B are separated by an «average» distance of 147 times the Earth - Sun distance (AU)(of a semi-major axis) in a circular orbit (e = 0.00) of about 2,600 years, in contrast to Josef Hopmann's (1890 - 1975) earlier report in 1958 of an elliptical orbit (e = 0.25) with an orbital period of 3,000 years and an «average» distance of 157 AU (of a semi-major axis) that varies between 118 and 196 AU.

at NCDC) when extended 1,000 years out = 20 Deg C, which would be around 4 times the rate of warming which took place during the especially intense period of rapid global warming for the first 1,000 years of the PETM.

According to the new Sixth Catalog of Orbits of Visual Binary Stars, Stars A and B have an «average» separation, or semi-major axis, of about 1.22 times the Earth - Sun distance (AU) in an eccentric orbit (e = 0.437), a period of about 2.25 years, and an inclination from the perspective of an observer on Earth of about 112.4 ° (Woitas et al, 2000).

I suffered from enlarged prostate (diagnosed benign prostatic hypertrophy and prostatitis with PSA = 10) with bleeding, obstruction of semen and urine, pain, urgency, frequency of urination etc (up to ten times per night) with symptoms increasing over a period of 30 years.

The policy lock - in period is 5 years, and I have paid all the five premiums on time (Rs 15k * 5Y = Rs 75k).

So if your bank is paying out an annual rate of interest of 1 %, compounded inifinitely over a period of one year, you could expect to have e ^ 0.01 = 1.01005 times your original principal in your bank account at the end of the year.

For example, if funds used to purchase a certificate of deposit (CD) are set to earn 4 % in interest per year and the rate of inflation for the same time period is 3 % per year, the real interest rate received on the investment is 4 % - 3 % = 1 %.

Actual money put toward debt over five years = $ 200,000 (as a result of interest accrued during this time period).

N = Number of compounding periods (how many times the calculations are done that compound money at the given interest rate, usually in months or years.

bloodborne arguably takes place in the 18th / 19th century while gothic architecture surfaced in the 12th / 13th centuries, so to make the argument that gothic = bloodborne is moot because they're two completely different time periods (separated by about 500 years).

FWIW even the denialist site icecap.us admits that it took «from the 1920s to the 1950s» (49 years) to get six of their 10 warmest years, and only from 1990 - 2008 (18 years) to get four more --(49/6) / (18/4) = 1.8 times as frequent in the more recent period.

There is an amusing numerological coincidence pointed out at the time by Charles Harrison: if you insert the periods p, masses m, and distances from the Sun d for the eight planets in the formula P = sum (p * m / d ^ 2) / sum (m / d ^ 2) you also get 11.295 years.

Now, I would rather very kindly suggest that for 25 < N < 35 (very roughly speaking, as it depends on the actual series of change points and p value used), what currently looks like a downward ending trend (small N and / or N / 2 problem) for N = 16 would continue upwards until the chosen p value was met and again descend close to p = 1 at the end point window (if, and a very big IF, anything like the current hiatus (IPCC AR5 uses that word like 53 times (Greg Laden even counted them for me)-RRB- period were to continue for another ~ 15 years).

4) the end results on the bottom of the first table (on maximum temperatures), clearly showed a drop in the speed of warming that started around 38 years ago, and continued to drop every other period I looked / /... 5) I did a linear fit, on those 4 results for the drop in the speed of global maximum temps, versus time, ended up with y = 0.0018 x -0.0314, with r2 = 0.96 At that stage I was sure to know that I had hooked a fish: I was at least 95 % sure (max) temperatures were falling 6) On same maxima data, a polynomial fit, of 2nd order, i.e. parabolic, gave me y = -0.000049 × 2 + 0.004267 x — 0.056745 r2 = 0.995 That is very high, showing a natural relationship, like the trajectory of somebody throwing a ball... 7) projection on the above parabolic fit backward, (10 years?)

The idea is that Jupiter's tides are 33 % higher at perihelion, hence the 1 / J, and if Saturn happens to be in conjunction [every 19.86 years] with Jupiter at that time the tides are even higher [a «spring tide» if you want], and because times are raised on both sides of the Sun, it will also happen if Saturn is on the other side of the Sun than Jupiter, hence every 19.86 / 2 = 9.93 years, so that is how the 60 - yr period comes about: 61 yr = 1 / (1/9.93 — 1/11.86).

My arithmetic for a 2x C02 would be: Present Warming: 0.75 deg C Current warming Rate 0.15 deg C per decade Time to 2x C02 (BAU scenario) approx 100 years So 0.15 x 10 +0.75 = 2.25 deg C Further warming due to time lag at end of 100 year period ~ 0.75 deg, probably over several decaTime to 2x C02 (BAU scenario) approx 100 years So 0.15 x 10 +0.75 = 2.25 deg C Further warming due to time lag at end of 100 year period ~ 0.75 deg, probably over several decatime lag at end of 100 year period ~ 0.75 deg, probably over several decades.

10 Temperature change over past 22,000 years Agriculture established Temperature change (C °) End of last ice age Average temperature over past 10,000 years = 15 °C (59 °F) Figure 20.2 Science: estimated changes in the average global temperature of the atmosphere near the earth's surface over different periods of time.

For example, taking some time periods with roughly constant slope, we have (slope x 1000 for easy reading): 1900 — 34: 1000 * slope = 1.23 / year (note CO2ref does not affect the slope) 1935 — 49: 1000 * slope = 0.114 / year (Depression, WWII etc) 1950 — 58: 1000 * slope = 1.67 / year (recovery stage 1) 1959 — 75: 1000 * slope = 2.92 / year (now things are moving) 1976 — 94: 1000 * slope = 4.36 / year (more and more growth) 1995 — 2011: 1000 * slope = 5.11 / year (China kicks in?)

Relaxing the assumption that benefits remain constant over time and assuming that the effect diminishes to zero by the end of the time period considered results in an estimated cost per QALY of # 56 885 for the 5 - year duration (probability cost - effective at # 20 000 = 30 %) and # 29 664 for the 10 - year time horizon (probability at the # 20 000 threshold = 44 %; table 8).

Goodyer et al. [14] interviewed mothers of children aged 8 — 16 years (n = 100) concerning stressful life events 12 months prior to the recent onset of anxiety, and mothers of matched controls (n = 100) about life events during an equivalent time period.

A total of 345 children (40.6 % female) presenting with a high level of CP in early elementary school (mean age at study inception = 8.52; SD =.94) were evaluated annually over a four - year period (5 measurement time points).

If so (300,000 X.08 = $ 24,000) is this paid out over a certain time period or within the first year, and once they reach that return we are squared away and splitting everything evenly (if we choose 50 - 50)?